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(333kg*m/s^2) (2.5x10^5m)

5 years ago

Answered By Mariam A

(333kg*m/s^2)(2.5*10^5m) = (8.3*10^7m^2/s^2


5 years ago

Answered By Denis B

(333kg*m/s^2)(2.5*10^5m) = (8.3*10^7m^2/s^2

Firstly, we must recognize that (333kg*m/s^2) is no more that (mass x acceleration) which is expressed as  F= ma  for a result of 333 Newtons. Then this result is multiplied by (2.5*10^5m) which is a distance. When we multiply force by distance we get units of work, known as joules. This final calculation gives us 8.33 x 10^7 joules of work.

 


5 years ago

Answered By Javad H

(333*2.5*105)(mass*acceleration*disposition) = 8.325*107(force*disposition) = 8.325*107 Joule