1. Addition and Subtraction of Radicals: Write each radical in simplest form.
A) 3sqrt(40) - 8sqrt(90)
B) 4sqrt(12) + 2sqrt(27) - 3sqrt(75)
C) sqrt(48) + sqrt(8) - sqrt(27) - sqrt(32)
D) sqrt(3x ^ 2) + sqrt(12x ^ 2)
E) sqrt(9x ^ 3) - sqrt(25x ^ 3) + x * sqrt(16x)
F) 3y * sqrt(24x ^ 2 * y ^ 2) + 6x * sqrt(54y ^ 3)
2. Multiplication of Radicals:
A) 2sqrt(3) * (7sqrt(5) - 5sqrt(3))
B) (4 + sqrt(3))(4 + sqrt(3))
C) (3sqrt(5) + sqrt(2)) ^ 2
D) sqrt(2x) * sqrt(6x ^ 3)
E) - 3sqrt(6 * 4 * sqrt(3))
F) (- 2x * sqrt(x * y ^ 2))(6y * sqrt(x ^ 2 * y))
G) sqrt(2x) * (sqrt(2) - sqrt(x))
H) (sqrt(2x) + sqrt(y))(sqrt(2x) - 5sqrt(y))
I) (2x - sqrt(3)) ^ 2
3. Division of Radicals
A) (sqrt(2))/(sqrt(14))
B) (25sqrt(3))/(5sqrt(15))
C) (12 + 2sqrt(5))/(sqrt(3))
D) (sqrt(x) - 2)/(sqrt(x))
E) sqrt x^ 3 * sqrt y^ 2 sqrt x^ 4 * sqrt y
F) ((7sqrt(2))(3sqrt(44)))/(2sqrt(3))
Posted 3 years ago by tim123 in Math 20-2 | 0 answers
#radicals
Ella installs lawn watering systems. The radius of sprayed water, r, in metres, can be expressed as
r=0.64A
where A represents the area watered, in square metres.
Ella has set each sprayer to spray at a radius of 1.2 m. Determine the area of grass watered by one sprayer, to the nearest tenth of a square metre.
Posted 3 years ago by tim123 in Math 20-2 | 1 answers
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