#3. In garden pea plants, the yellow seed colour (Y) is dominant over the green see colour (y). What are the genotypes of heterozygous yellow seeds and homozygous recessive seeds repectively? a). Yy&YY. b).yY&yy.c).Yy &yy d).Yy& yY. I think that the answer they are looking for is A but i am not sure. 

#4.In garden pea plants, the purple flower color (P) is dominant over the white color flower (p). What are the phenotypes of homozygous dominant and heterozygous flowers, respectively? Select: a). White and purple. b). Purple & qhite c). White & white. d). Purple, purple. I think it is b but im not sure

#5. In fruit flies, grey body color (G) is dominant over black body clour (g). A cross between a heterozygous grey fruit fly and a black fruit fly can be represented by a). Gg x Gg b). Gg x GG c). Gg x gg. d). GG x gg. I think it is D but i am not sure.  

#6. In fruit flies, long wings (L) are dominant over short wings(l). LL,Ll and ll represent a). Three genotypes. b). three dominants. c). three phenotypes. d). three true breeding crosses. I think it is b.

#7. when a trait is only expressed in the presence of two identical alleles, the genotype is: a). Homozygous dominant. b). Homozygous recessive. c). Heterozygous recessive. d). Hetrozygous dominant. I think it is a but again not sure. 

#8. In sheep a hairy coat (H) is dominant over a wooly fleece(h). The phenotype of a heterozygous sheep and a homozygous recesive sheep are repspectively, a). Hairy and hairy. b). hairy and wooly. c). HH and hh. d). Hh and hh. 

#9. In garden pea plants, the yellow seed colour (Y) is dominant over the green seed color(y). A true breeding yellow-seeded plant was crossed with a green-seeded plant. All of the F1 generation plants had yellow seeds. Which of the following states is true for the F1 generation? a). None of the F1 generation plants will have the same allele for green seeds. b). Half of the F1 generation plants will have the same allele seeds for yellow seeds. c). All of the F1 generation plants will have the allele for green seeds. d). None of the F1 genertation plants will have allele for yellow seeds. 

#10. In mice, the waltzing allele (w) that causes the mouse to run in circles due to an inner ear defect is recessive to the non- waltzing allele(W). If a heterozygous mouse mated wit ha walting mouse. If a heterozygous mouse mated with a waltzing mouse, a). 100% of the offspring would have a copy of the recessive allele. b). 75% of the offspring would have the dominant trait. c).100% of the offspring would have the same copy of the dominant allele. d). 75% of the offspring would have the recessive trait.

#11. Use the following info for question 12 as well. In mice, albinism (g) IS recessive to grey coat colour (G). A grey mouse mated with an albino mouse. Over the course of several months, 38 pups were born. Out of 38 pups, 17 had a grey coat and 21 were albino. Which of the following rows correcrly identifies the parental and F1 generation genotypes? a). Parental corss GgxGG F1 Genotypes GGxGg. b). Parental cross GGxgg F1 generation Gg. c).Ggxgg F1 generation GG, Gg and gg. d).Gg x gg F1 generation F1Gg and gg. 

#12. Theoretically what is the excepted result from the parental cross of a grey mouse and albino mouse, and why does teh excpeted result not match the result stated in the information given above? a). Theoretically, there should be a 1:1 ratio of grey mice to albino mice, or grey coat mice and 19 albino mice. With more litters, the actual results would match the expected results more closely. b). Theoretically, 100% of the mice should have grey coats so all 38 offspring should have grey coats. There was an experimental error that can account for the deviation.c). Theoretically, there should be a 3:1 ratio of grey mice to albino mice, or 29 grey coat mice and 9 albino mice. With more litters, the actual results would match the expected results more closely.d). Theoretically, there should be a 3:1 ratio of grey mice to albino mice, or 28.5 grey coat mice and 9.5 albino mice. There was an experimental error that can account for the deviation.

#13. Which of the following statements describes the law of segregation? a). A Punnett square can be used to predict the outcome of a parental cross. b). the dominant allele is represented with an uppercase letter and the recessive allele is represented with alowercase letter.c). Dominant alleles are always expressed in a homozygous or heterozygous individual.d). A Bb individual will produce B and b alleles, while a bb individual will only produce a b allele.

Hi there, i need help with these questions. Please help me with this when you see my post. Please and thank you :)

ParthenogenesisSome animals in captivity have reproduced without the need for a mate in a process called parthenogenesis. Examples include boas, pythons, bonnethead sharks, and komodo dragons. Initially, scientists thought this occurred because the animals were kept in optimal conditions for reproduction, but lacked access to a mate. However, scientists were surprised to discover that some species in the wild with access to mates also reproduce through parthenogenesis. An example is the pit-viper. Compare and contrast the processes of sexual reproduction and asexual reproduction through parthenogenesis for an animal such as the pit-viper. 

when a neuron is stimulated what happens?

#9. Germ cells are specialized cells that develop into gametes. Gametes are produced through the process of meiosis. If the diploid number for humans is 46 chromosomes, how many chromatids does a cell undergoing meosis have at each following stage? a). Growth phase 2 of interphase ( 92) MetaphaseI(46) Prophase II(46) End of Telophase( 23). b). Growth phase 2 of interphase ( 92) Metohpase I( 92) Prophase II( 46) End of telophase(0). c). Growth phase 2 of interphase ( 46) MetaphaseI(46) ProphaseII(23) End of telophase (23). d). Growth phase 2 of interphase ( 46) Metaphase 1( 92) ProphaseII(23) End of telopase(0). I think the answer they're asking for is either b or d, but im not sure. 

#10.in an organism with a diploid number of 16, how many chromatids are present in mitotic phase, meiotic phase I, meiotic phase II and metotic telophase II. So far i have 32 for mitotic phase, 32 for meiotic phase I and 16 for meiotic phase II and for meiotic telophase II i have 0. Not sure if this is even correct or not. 

#16. The DNA in a sunbather's skin cells may mutate after prolonged exposure to the sun. The process that will pass the mutation along to daughter cells is __(1)_, which is a muation that will ___(2)__. a). process(1) mitosis description (2) be inhereted by the children of sunbather. b). process (1) meosis description (2) be inhereted by the children of sunbather. c). process(1) meoisis description (2) not be inhereted by the children of sunbather. d). process(1)mitosis desription(2) not be inherted by the children of sunbather. i think it;s b but again im not sure. 

#22. The diploid chromosome of a cat, Felis catus, 38. which of the following rows correctly identifies the number of egg cells and chromosomes in each cell after the process of oogenesis has completed? a).# of cells ( 3) # of chromosomes (114). b). # of cells (2) # of chromosomes (38). c). # of cells(1) # of chromosomes( 19). d). # of cells(4) # of chromosomes(19). i think it's b but i'm not sure. 

#23. The diploid chromosome number of a dog, Canis familiaris, is 78. which of the following rows correctly identifies the number of egg cells and chromosomes in each cell after the process of spermatogenesis has completed? a).# of cells (4) # of chromosomes(39).b) # of cells(3) # of chromosomes(29).c). # of cells(2) # of chromosmes(78). d).# of cells(1) # of chromosmes(39). I think the answer is a but again i'm not sure. 

#30. Oogenesis involves germ cells in the ovary undergoing meiosis to produce a functional ovum at the end of the process. which of the following cells is penentrated by a sperm cell during the process of fertlization? a). ovum, b). secondary oocyte, c).Oogina, d).primary Oocyte. 

#34. why is parthenogenesis in bees consisdered to be a form of asexual reproduction? a). the male drone is made from a haploid egg. fertilization is not part of the process to make a male drone. b). although genetic material is transferred from one egg cell to another using conjugation, the resulting cells will be identical to each other. c). the formation of the original haploid cell was achieved using binary fusion. d). the haploid male bees were made through the process of meiosis, so they are identical to the parent cell. i think it is d; but i'm not sure. 

#36. since the seedless bananas are tripolid(3n), and  do not produce viable seeds for reproduction. To grow more seedless banana plants, farmers take a sideshoot and replant it. this type of asexual reproduction is called: a). binary fusion, b). fragmentation, c).parthenogenesis,d).budding. i think it's a but again i am not sure if this is even correct or not. 

#38.  what is the polidy of zygote during the cycle of toxoplasma gondil? a). 1n, b). 2n, c).4n, d). 3n.  i think it is b. but i am not sure

#39. the haploid genome of toxoplasma gondii has 14 chromosomes. when oocyst changes into sporozoite, its nucleus contains: a). 28 chromosomes b).14 chromosomes c). 42 chromosomes d). 7 chromosmes. i think it is a because 2*14 is 28. 

Please get back with me today, if you can. Thank you and have a good day! :)

#3.DNA contains the genetic information that controls all processes of heredity in a cell. The total length of all DNA in the cells of a human body can stretch to the moon and back four times. The correct term below that desribes the length of a DNA and the form in which it remains in most of itslife is respectively: a). Length of DNA ( Chromosome) Form in which it spends most of its life time ( Chromatin). b). Length of DNA (centromere) Form in which it spends most of its life time( telemore). c). Length of DNA (centromere) Form in which it spends most of its life time(locus). d). length of DNA(chromosome) Form in which it spends most of its life time( centromere). 

Hi, i have posted this question before, but it hasn't been answered. Thank you, and have a good day:)

#4.which of the following cells undergo mitosis? 

a). Epithelium cells 

b). Nerve cells

C). Red blood cells 

d). Stereocilia 

i think the answer is C red blood cells but im not sure. 

#5. in a cell cycle 

a). DNA and RNA are replicated and passed to parent cells during interphase 

b). DNA is replicated and passed to homologous chromosomes during interphase

c). DNA is replicated and passed to daughter cells during mitosis

d). DNA and RNA are replicated and passed to sister chromatids during miotic phase

i think the answer is b but im not sure

#6. when analyzing a normal human male karyotype, all of the chromosomes can be stored into homologous pairs EXCEPT: a). autosomal chromosome number 18. b). sex chromosomes. c). chromosome pair number 21. d). X chromosomes. I think the answer is D but again i am not 100% sure. 

#7. which of the following statements does NOT correctly desciribe the characterisitics of homologous chromosome? a). the size and shape of the chromosomes are the same. b). they contain the same genes. c). they contain identical alleles. d).they have centromeres located at the same spot.

#9. Autosomal homologous chromosomes: a). are all the same size but different shape. b). are joined at the centromere. c). have identical gene locations and alleles. d). consists of a copy of the parental and maternal chromosome.

#18. Identify the main phases of interphase in the correct order: a). growth, mitosis and cytokinesis. b). growth and synthesis. c). growth, synthesis and mitosis. d). growth 1, synethsis, growth 2. I think the answer is d. But again im not sure. 

Hi there, the reason why i decided to post all of the questions that i have is becasue i am unable to post more than 1 post for some odd reason. I also posted a question last night and no one got back with me. Please get back with me today. Thank you and have a good day! 

DNA contains the genetic information that controls all processes of heredity in a cell. The total length of all DNA in the cells of a human body can stretch to the moon and back four times. The correct term below that desribes the length of a DNA and the form in which it remains in most of itslife is respectively: a). Length of DNA ( Chromosome) Form in which it spends most of its life time ( Chromatin). b). Length of DNA (centromere) Form in which it spends most of its life time( telemore). c). Length of DNA (centromere) Form in which it spends most of its life time(locus). d). length of DNA(chromosome) Form in which it spends most of its life time( centromere)

Which of the following situations correctly illustrates the all or non principle? 

select one: 

a.) A smaller voltage change will result in a smaller nerve impulse 

b.) A faster impulse can be generated with a voltage change that is greater than the threshold potential.

c.) A stronger impulse can be generated by increasing the number of open voltage-gated sodium channels during depolarization.

d.) A greater voltage change and a smaller voltage change will result in the same action potential as long as the threshold potential has been reached.

Which of the following is NOT a reason why a reflex arc is faster than a normal nerve transmission 

select one: 

a.) a reflex arc does not send information to the brain to be processed 

b.) A reflex arc does not involve neurotransmitters 

c.) A reflex arc stimulates the motor neurons for an immediate reaction 

d.) A reflex arc involves fewer neurons 

A woman taking birth controls pills would expect to have 

select one:

a.) Higher than normal FSH and LH levels due to fewer negative feedback messages being sent to the ovaries 

b.) Lower than normal FSH and LH levels due to more neagtive feedback messages being sent the pituitary gland 

c.) Higher than normal FSH and LH levels due to fewer negative feedback messages being sent to the pituitary gland 

 d.) Lower than normal FSH and LH levels due to more neagtive feedback messages being sent the ovaries