You are travelling down a highway at 110km/h when you notice a turn up ahead that you will need to slow down for. You apply your breaks, which you know causes an acceleration of 2.15m/s^2 for 6.8s. Determine the final velocity
Posted 8 years ago by Feven17 in Physics 20 | 1 answers
#velocity
my daughter just finished ELA 10-1 with and overall grade of 65% We both feel she could use some help before moving on. If she were do redo some of the assignments and post them here would anyone there be able to provide feedback for improvement?
Posted 8 years ago by a.darichuk in English 10-1 | 5 answers
#language arts 10 1
Given the reaction 2SO2 + O2 ---> 2SO3
Eq constant is 2.8X102 at 727 $^{\circ}$? C
Is the percentage of sulfur dioxide that reacts with oxygen at this temperature relatively large or relatively small? How does the percentage of SO2(g) that reacts compare with the percentage of O2(g) that reacts?
Posted 8 years ago by ilikeyou in Chemistry 30 | 1 answers
#equilibrium
What is the H3O+ (aq) concentration of a strong acid with a pH of 0.24?
Posted 8 years ago by arqum99 in Science 30 | 2 answers
#science 30
What were the consequences of the rebellion for louis riel
Posted 8 years ago by amira321 in Social Studies 10-1 | 1 answers
#louis riel reseach assigment
You built a pendulum clock. How far from the pivot should you place the center of the pendulum mass for a period that is 3.6 secondes
Posted 8 years ago by in Physics 20 | 1 answers
#simple harmonic motion
A and B are in quadrant 1. Sin A = (4/5) and cos B = (7/9). Give an exact value for Sin (A+B).
Posted 8 years ago by grk546 in Math 30-1 | 1 answers
#trigonometry
Given N2(g)+O2(g)<--> 2NO(g) Keq=8.00 *10-2 at 500 C
In a 2.00L flask, 0.4 mol of N2 and 0.4 mol of oxygen gas, O2, reacted to equilibrium. Establish the equilibrium concentration of all the gases.
(Answer: [N2]=0.175 mol/L; [O2] = 0.175 mol/L; [NO] = 0.0496 mol/L) This one has got a quadratic I can't figure out
My first step: $\frac{\left(2x\right)}{\left(0.2-x\right)^2}=0.08$(2x)(0.2−x)2 =0.08
My second step: $0.08\cdot\left(.2-x\right)\left(.2-x\right)=2x$0.08·(.2−x)(.2−x)=2x
Don't know what's next
Posted 8 years ago by grk546 in Chemistry 30 | 1 answers
#equilibrium
Given the reaction PCl5(g)<--> PCl3(g)+Cl2(g)
In a 1.00 L flask, 0.72 mol of PCl5 and 0.18 mol of PCl3 are mixed together. Reaction occurrred to equilibrium and tests showed that 0.60 mol of PCl5 was now present. Calculate the Keq value.
(Answer: 6.0*10-2)although I cannot figure out how to find this without a given value from Cl2.
Posted 8 years ago by grk546 in Chemistry 30 | 1 answers
#equilibrium
write $2\log_bx-\frac{\log_bZ}{2}$2 logbx− logbZ2 as a single logarithm
Posted 8 years ago by mathlete in Math 30-1 | 2 answers
#logs