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A 1000kg elevator accelerates up a shaft at a rateof 2.0 m/s2. The tension in the cable raising the elevator is?

A. 12 kN

B. 9.8 kN

C. 7.8 kN

D. 2.0 kN

8 years ago

Answered By Jonathan D

Ft=Force of Tension=?

Fg=Force of Gravity = mass*gravity=1000kg*9.81m/s^2

m=mass=1000 kg

a=acceleration=9.81m/s^2

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8 years ago

Answered By Hossein M

  $\Sigma$Σ Ftotal =ma, Ft(tension force) - mg = ma, Ft = m(g+a)=1000(10+2)=12000=12kN

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8 years ago

Answered By Victor A

 

Applying Newton’s second law of motion (*) and after setting up the Force balance in the elevator:

 

Ft = m (a + g) = 1000 (2.0 + 9.8 m/s2) = 1000 (11.8) = 11.8 KN ~ 12 KN

 

(*) Let us recall that Newton’s second law can be defined as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object. I hope the answer can help the student who posted it.

 


8 years ago

Answered By Iluminado C

T=m(g+a)=1000kg(9.8m/s2 + 2m/s2)= 12kN


8 years ago

Answered By Negar S

Elevator wieght cause a force of 

W= m.g

there is a tension in the rod of elevator in the opposite direction of wieight... Elevator is moving upward right?

i

It means Newton formula can be written as :

m.a = Ft - Fg

or 

Ft=ma+Ft

or

Ft=m.a + m.g = m. (a+g) 

Ft = 1000(kg). ( 2m/s2 + 9.81 m/s2) = 11.8 kN

 

IMPORTANT NOTE : Always pay attention to the units.