A 37.8 kg child is standing on a scale in an elevator.Determine the reading on the scale if the elevator is accelerating upwards at 4.1om/s^2
1 month ago
Answered By Dhruvin P
When an elevator accelerates upward, it creates an additional apparent force that adds to gravity. Think of it like this - when you're in an accelerating elevator going up, you feel "heavier." Here's how we solve it:
Step 1: Identify the forces
Normal force (scale reading) = mass × (gravity + acceleration)
We use (g + a) because the acceleration adds to gravity when moving upward
Step 2: Plug in the values
Mass = 37.8 kg
g = 9.81 m/s²
a = 4.10 m/s²
Scale reading = 37.8 × (9.81 + 4.10) = 37.8 × 13.91 = 525.8 N
1 month ago
Answered By Dhruvin P
When an elevator accelerates upward, it creates an additional apparent force that adds to gravity. Think of it like this - when you're in an accelerating elevator going up, you feel "heavier." Here's how we solve it:
Step 1: Identify the forces
Normal force (scale reading) = mass × (gravity + acceleration) We use (g + a) because the acceleration adds to gravity when moving upwardStep 2: Plug in the values
Mass = 37.8 kg g = 9.81 m/s² a = 4.10 m/s² Scale reading = 37.8 × (9.81 + 4.10) = 37.8 × 13.91 = 525.8 N