A 70.0g sample of water at 95.00C is mixed with 50.0g of water at 135C. Calculate the final tempreture of the mixture assuming no heat loss to the surroundings. Remember that the heat gained by the cooler water is equal to the heat lost by the warmer water.
6 years ago
Answered By Naim S
We start by calling the final, ending temperature 't.' Keep in mind that BOTH water samples will wind up at the temperature we are calling 't.' Also, make sure you understand that the 't' we are using IS NOT the Δt, but the FINAL temperature. This is what we are solving for.
The warmer water goes down from to 135 to t, so this means its Δt equals 135 minus t. The colder water goes up in temperature (from 95 to the ending temperature), so its Δt equals t minus 95.
6 years ago
Answered By Naim S
We start by calling the final, ending temperature 't.' Keep in mind that BOTH water samples will wind up at the temperature we are calling 't.' Also, make sure you understand that the 't' we are using IS NOT the Δt, but the FINAL temperature. This is what we are solving for.
The warmer water goes down from to 135 to t, so this means its Δt equals 135 minus t. The colder water goes up in temperature (from 95 to the ending temperature), so its Δt equals t minus 95.
Q gained = Q lost
mcΔt (gained) = mcΔt (lost)
70.0x 4.19x (t-95) = 50.0x 4.19x (135-t)
Solve for t, t = 111.667deg Celcius = 112 deg C