A and B are in quadrant 1. Sin A = (4/5) and cos B = (7/9). Give an exact value for Sin (A+B).
8 years ago
Answered By Charles S
Sin(A+B) needs to be expanded using the identity Sin(A+B) = Sin(A)Cos(B) + Cos(A)Sin(B). As you can see, we weren't given Cos(A) or Sin(B) in the question. See the whiteboard on how I obtained those values.
Then all you have to do is substitute the values in:
8 years ago
Answered By Charles S
Sin(A+B) needs to be expanded using the identity Sin(A+B) = Sin(A)Cos(B) + Cos(A)Sin(B). As you can see, we weren't given Cos(A) or Sin(B) in the question. See the whiteboard on how I obtained those values.
Then all you have to do is substitute the values in:
$\left(\frac{4}{5}\right)\left(\frac{7}{9}\right)+\left(\frac{3}{5}\right)\left(\frac{4\sqrt{2}}{9}\right)$(45 )(79 )+(35 )(4√29 )
And simplify
$\frac{28}{45}+\frac{12\sqrt{2}}{45}=\frac{28+12\sqrt{2}}{45}$2845 +12√245 =28+12√245
Attached Whiteboard:
Play Drawing