Answered By Harsh P

Decreament in P.E.= Increament in K.E.

mg(h₁ - h₂) = m(V₂²- V₁²)

9.8 ( 225-115) = V₂² - 36²

so,V₂²= 2374

V2= 48.72

Answered By Harsh P

Decreament in P.E.= Increament in K.E.

mg(h1 - h2) =(1/2) m(V22- V12)

9.8 ( 225-115) = (1/2)*(V22 - 36²)

so,V22= 3452

V2= 58.75

Sorry for previous solution

Answered By Majid B

 $E_i=E_f$E_i=E_ƒ                            =>          $E_{ki}+E_{pi}=E_{kf}+E_{pf}$E_ki+E_pi=E_kƒ +E_pƒ       =>        $\frac{1}{2}mv_i^2+mgh_i=\frac{1}{2}mv_f^2+mgh_f$12 mv_i²+mgh_i=12 mv_ƒ ²+mgh_‍ƒ      =>   $\frac{1}{2}v_i^2+gh_i=\frac{1}{2}v_f^2+gh_f$12 v_i²+gh_i=‍12 v_ƒ ²+gh_ƒ      =>          $v_f^2=v_i^2+2g\left(h_i-hf\right)$v_ƒ ²=v_i²+2g(h_i−hƒ )     =>        $v_f=\sqrt{v_i^2+2g\left(h_i-hf\right)}$v_ƒ =√v_i²+2g(h_i−hƒ )              =>     $v_f=\sqrt{36^2+2\times9.81\left(225-115\right)}$v_ƒ =√36²+2×9.81(225−115)   

$v_f=58.77$v_ƒ =58.77 m/s