#3. In garden pea plants, the yellow seed colour (Y) is dominant over the green see colour (y). What are the genotypes of heterozygous yellow seeds and homozygous recessive seeds repectively? a). Yy&YY. b).yY&yy.c).Yy &yy d).Yy& yY. I think that the answer they are looking for is A but i am not sure. 

#4.In garden pea plants, the purple flower color (P) is dominant over the white color flower (p). What are the phenotypes of homozygous dominant and heterozygous flowers, respectively? Select: a). White and purple. b). Purple & qhite c). White & white. d). Purple, purple. I think it is b but im not sure

#5. In fruit flies, grey body color (G) is dominant over black body clour (g). A cross between a heterozygous grey fruit fly and a black fruit fly can be represented by a). Gg x Gg b). Gg x GG c). Gg x gg. d). GG x gg. I think it is D but i am not sure.  

#6. In fruit flies, long wings (L) are dominant over short wings(l). LL,Ll and ll represent a). Three genotypes. b). three dominants. c). three phenotypes. d). three true breeding crosses. I think it is b.

#7. when a trait is only expressed in the presence of two identical alleles, the genotype is: a). Homozygous dominant. b). Homozygous recessive. c). Heterozygous recessive. d). Hetrozygous dominant. I think it is a but again not sure. 

#8. In sheep a hairy coat (H) is dominant over a wooly fleece(h). The phenotype of a heterozygous sheep and a homozygous recesive sheep are repspectively, a). Hairy and hairy. b). hairy and wooly. c). HH and hh. d). Hh and hh. 

#9. In garden pea plants, the yellow seed colour (Y) is dominant over the green seed color(y). A true breeding yellow-seeded plant was crossed with a green-seeded plant. All of the F1 generation plants had yellow seeds. Which of the following states is true for the F1 generation? a). None of the F1 generation plants will have the same allele for green seeds. b). Half of the F1 generation plants will have the same allele seeds for yellow seeds. c). All of the F1 generation plants will have the allele for green seeds. d). None of the F1 genertation plants will have allele for yellow seeds. 

#10. In mice, the waltzing allele (w) that causes the mouse to run in circles due to an inner ear defect is recessive to the non- waltzing allele(W). If a heterozygous mouse mated wit ha walting mouse. If a heterozygous mouse mated with a waltzing mouse, a). 100% of the offspring would have a copy of the recessive allele. b). 75% of the offspring would have the dominant trait. c).100% of the offspring would have the same copy of the dominant allele. d). 75% of the offspring would have the recessive trait.

#11. Use the following info for question 12 as well. In mice, albinism (g) IS recessive to grey coat colour (G). A grey mouse mated with an albino mouse. Over the course of several months, 38 pups were born. Out of 38 pups, 17 had a grey coat and 21 were albino. Which of the following rows correcrly identifies the parental and F1 generation genotypes? a). Parental corss GgxGG F1 Genotypes GGxGg. b). Parental cross GGxgg F1 generation Gg. c).Ggxgg F1 generation GG, Gg and gg. d).Gg x gg F1 generation F1Gg and gg. 

#12. Theoretically what is the excepted result from the parental cross of a grey mouse and albino mouse, and why does teh excpeted result not match the result stated in the information given above? a). Theoretically, there should be a 1:1 ratio of grey mice to albino mice, or grey coat mice and 19 albino mice. With more litters, the actual results would match the expected results more closely. b). Theoretically, 100% of the mice should have grey coats so all 38 offspring should have grey coats. There was an experimental error that can account for the deviation.c). Theoretically, there should be a 3:1 ratio of grey mice to albino mice, or 29 grey coat mice and 9 albino mice. With more litters, the actual results would match the expected results more closely.d). Theoretically, there should be a 3:1 ratio of grey mice to albino mice, or 28.5 grey coat mice and 9.5 albino mice. There was an experimental error that can account for the deviation.

#13. Which of the following statements describes the law of segregation? a). A Punnett square can be used to predict the outcome of a parental cross. b). the dominant allele is represented with an uppercase letter and the recessive allele is represented with alowercase letter.c). Dominant alleles are always expressed in a homozygous or heterozygous individual.d). A Bb individual will produce B and b alleles, while a bb individual will only produce a b allele.

Hi there, i need help with these questions. Please help me with this when you see my post. Please and thank you :)

Which of the following statements correctly identifies the difference between plant and animal cells division? 

a.) Both plant and animal cells undergo mitosis and cytokinesis, but they lack the interpase 

b.) plant cells lack centrioles, and they form a cell plate during cytokinesis 

c.) Plant cells lack centomeres, and they form a cell to produce two daughter cells 

d.) The cell walls of the plant prevent the process of cytokinesis 

#1. Which of the following statements correctly describes the Law of Independent Assortment? Select one:a). Non-allelic genes do not affect each other if they are located on separate chromosomes.b). A large Punnett square can be used to predict the outcome of a parental cross involving two traits.c). The dominant allele is represented with an uppercase letter and the recessive allele is represented with a lowercase letter.d). Sometimes all alleles lack dominance, which leads to a blending of traits.

Use the following information to answer the next question.The Labrador Retriever’s coat colours are black, yellow, and chocolate.Yellow is produced by the presence of a recessive epistatic gene, which has the effect of masking the black and chocolate colour genes. Black (B) is dominant to chocolate (b). Therefore, the possible genotypes and corresponding phenotypes are:

Predict the percentage of offspring that would be black in colour for each of the following crosses. Record your answer as a whole number. 

A couple has one daughter with Tay-Sachs disease and three other unaffected children. Neither the mother, nor father, nor any of the biological grandparents of the affected daughter have had the disease. Tay-Sachs disease most likely demonstrates what type of inheritance? Select one: a). autosomal recessive. b). X-linked dominant. c). autosomal dominant. d). X-linked recessive

I think it is b but i am not sure please help me out. Thank you so much and have a great day

Recombination frequency question. The recombinant frequency of two genes A and B located on the same chromosome is 38%. Parents heterozygous for genes A and B were test crossed, and 250 offspring resulted. How many of the offspring would have the parental genotypes ofr A and B?

I was told that you have to use this formula : recombination frequency= # of recombinant types / total number of offspring x 100%. I did this. I went 0.38= # of recombinant types / 250 offsprings x 100%. i got rid off the 100% to get 0.38 i took 0.38 x 250 i ogt 95. is my answer correct?

Some processes involved in DNA replication

1. the replication origin is identified

2.DNA primase builds RNA primer

3. Okazaki fragments are spliced by DNA ligase

4. Helicase bind and uncoil the DNA double helix

5. RNA primer is the starting point for DNA polymerase

6. DNA replication ends at the telomere where DNA codes for termination

7. DNA polymerase adds complementary nucleotides in the 5' to 3' direction in short segments called Okazaki fragments

The sequence in which the events numbered above occur during DNA replication of the lagging strand is

Hi there, i really need help with this question please get back with me. Thank you 

Sources of mutation:

1. prolonged skin exposure to UV rays

2. mother is a carrier of sex-linked trait

3. homologuous chromosmes fail to seperate during meiosis

4. dna polymerase adds incorrect nucleotide during interphase of mitosis

identify whether the sources of mutations listed above are somatic cell mutation or germ line mutation. 

1. somatic cell mutation

2. germ line muation

types of muations:

sources of mutation: a,b,c,d

Which of the following statements correctly describes the function of mitochondria found in axon terminals?

a.) They synthesize ATP, which is required for the prodcution of neurotransmitters 

b.) They synthesize enzymes, which are required to break down the neurotransmitters.

c.) They synthesize vesicles, which transport sodium and potassium ions across the synpase

d.) They synthesize ATP, which is required to bond the axon terminal to the dendrites.