Given $
Y-k=a\
left(x-h\
right)^2$ Y−k=a(x−h)2 , a=1, h<0, k>0, which quadrant is the vertex in?
8 years ago
Answered By Qi (Jeff) J
Since h<0 which indicates a left shift So it has to be in quadrant 2 and 4
Then we have k>0 which means a upward shift so it has to be in quadrant 1 and 2.
Since quadrant 2 is the only quadrant that fits both criteria then quadrant 2 is the answer
8 years ago
Answered By Sujalakshmy V
The equation Y-k=a(x-h)2 can be written as Y=a(x-h)2+k
The vertex of this equation is (h,k)
As it is given in the question, h<0, the x co-ordinate of the vertex will be in the quadrant 2 or 3.
Again as k>0, the y cordinate of the vertex will be in the quadrant 1 or 2.
Hence the vertex which matches two criteria will be a vertex in the quadrant 2.
So,Quadrant 2 is the answer.
6 years ago
Answered By Peter O
Y = a(x-h)2 + k, a = 1, h$<$<0 and k$>$>0
x - h = 0 $\rightarrow$→ x =h
Y = a(x-h)2 + k
= a(0)2 + k$\rightarrow$→ Y = k
The vertex of Y = a(x-h)2 + k is at (x=h, y=k) that is the coordinate (h,k) which is in the 2nd Quadrant since h is in the negative x-axis and k is in positive y-axis.
8 years ago
Answered By Qi (Jeff) J
Since h<0 which indicates a left shift So it has to be in quadrant 2 and 4
Then we have k>0 which means a upward shift so it has to be in quadrant 1 and 2.
Since quadrant 2 is the only quadrant that fits both criteria then quadrant 2 is the answer
8 years ago
Answered By Sujalakshmy V
The equation Y-k=a(x-h)2 can be written as Y=a(x-h)2+k
The vertex of this equation is (h,k)
As it is given in the question, h<0, the x co-ordinate of the vertex will be in the quadrant 2 or 3.
Again as k>0, the y cordinate of the vertex will be in the quadrant 1 or 2.
Hence the vertex which matches two criteria will be a vertex in the quadrant 2.
So,Quadrant 2 is the answer.
6 years ago
Answered By Peter O
Y = a(x-h)2 + k, a = 1, h$<$<0 and k$>$>0
x - h = 0 $\rightarrow$→ x =h
Y = a(x-h)2 + k
= a(0)2 + k $\rightarrow$→ Y = k
The vertex of Y = a(x-h)2 + k is at (x=h, y=k) that is the coordinate (h,k) which is in the 2nd Quadrant since h is in the negative x-axis and k is in positive y-axis.