Given that 3^10 = 59,049, what is 3^-10 expressed as an exact value?
6 years ago
To get an exact solution we will use the exponent law: y^(-x) = 1/(y^x).
In this case y=3 and x=10. We know 3^(-10) = 1/3^10 = 1/59049 (we take this number directly from the question)
x-n= $\frac{1}{x^n}$1xn
3-10= $\frac{1}{3^{10}}$1310 = $\frac{1}{59049}$159049
3-10= $\frac{1}{59049}$159049
3^(-10)=1/(3^10)=1/59049
6 years ago
Answered By Alexandria M
To get an exact solution we will use the exponent law: y^(-x) = 1/(y^x).
In this case y=3 and x=10. We know 3^(-10) = 1/3^10 = 1/59049 (we take this number directly from the question)
6 years ago
Answered By Bahareh M
x-n= $\frac{1}{x^n}$1xn
3-10= $\frac{1}{3^{10}}$1310 = $\frac{1}{59049}$159049
3-10= $\frac{1}{59049}$159049
6 years ago
Answered By Sujalakshmy V
3^(-10)=1/(3^10)=1/59049