Compound interest is solved with the equation A=P(1 + r/n)(nt)
First I'll break down how to read this, then ill give you a practice problem with it so you understand the application as well
A: is what you're solving for, the total amount of the future investment based on some monetary gain over some stretch of time
P: is the principal investment, also known as how much cash you initially invested to gain interest on
r: the annual interest rate, as a decimal not percent, 12% interest is represented by 0.12 in the equation
n: the number of times the compound takes effect within a year, so if its annually, n is 1, if its monthly, n is 12, quarterly is 4 etc.
t: how long you invested money for
Practice problem solve:
assume you invest $5000 into a savings account that has an interest rate return of 5% a year, compounded annually. How much money would you have after 10 years?
P= $5000
r= 5%= 0.05
n=1 because it only returns 5% after a full year, so one time
t= 10
A=P(1+(r/n))(nt)
A= 5000(1+(0.05/1))(1x10)
A= $8144.47
so the investment would grow to $8144.47 when compounded annually for 10 years
3 years ago
Answered By Arsalan Q
Compound interest is solved with the equation A=P(1 + r/n)(nt)
First I'll break down how to read this, then ill give you a practice problem with it so you understand the application as well
A: is what you're solving for, the total amount of the future investment based on some monetary gain over some stretch of time
P: is the principal investment, also known as how much cash you initially invested to gain interest on
r: the annual interest rate, as a decimal not percent, 12% interest is represented by 0.12 in the equation
n: the number of times the compound takes effect within a year, so if its annually, n is 1, if its monthly, n is 12, quarterly is 4 etc.
t: how long you invested money for
Practice problem solve:
assume you invest $5000 into a savings account that has an interest rate return of 5% a year, compounded annually. How much money would you have after 10 years?
P= $5000
r= 5%= 0.05
n=1 because it only returns 5% after a full year, so one time
t= 10
A=P(1+(r/n))(nt)
A= 5000(1+(0.05/1))(1x10)
A= $8144.47
so the investment would grow to $8144.47 when compounded annually for 10 years
Hope this helped :)