if r > 0 and s >0, then the solution to the inequality 3(x-r)2 >s will cover more of the number line when
a. r is increased
b. r is decreased
c. s is increased
d. s is decreased
7 years ago
If x $>$> r, then x $>$> r+ $\sqrt{ }$√ s/3,
If x $<$< r, then x < r - $\sqrt{ }$√ s/3, see drawing:
not covered part is 2 r = r + $\sqrt{ }$√ s/3 + r- $\sqrt{ }$√ s/3, if r increased, then cover less of line number,
If r decreased, cover more of line number.
so correct number is b).
Not cover number line shall be 2 $\sqrt{ }$√ s/3 = ( r+ $\sqrt{ }$√ s/3) - ( r - $\sqrt{ }$√ s/3), so S decreased, cover more of line number. Correct answer is d).
7 years ago
Answered By Xuezhong J
If x $>$> r, then x $>$> r+ $\sqrt{ }$√ s/3,
If x $<$< r, then x < r - $\sqrt{ }$√ s/3, see drawing:
not covered part is 2 r = r + $\sqrt{ }$√ s/3 + r- $\sqrt{ }$√ s/3, if r increased, then cover less of line number,
If r decreased, cover more of line number.
so correct number is b).
Attached Whiteboard:
Play DrawingAttached Graph:
7 years ago
Answered By Xuezhong J
Not cover number line shall be 2 $\sqrt{ }$√ s/3 = ( r+ $\sqrt{ }$√ s/3) - ( r - $\sqrt{ }$√ s/3), so S decreased, cover more of line number. Correct answer is d).