If the point (4,7) lies on the graph of 2y+2 = f(1/5(x-1)) what is the corresponding point on the graph of y=f(x)?
3 years ago
From the equation they gave us, we know f(1/5(x-1)) = f(4)
So this means that 4 = 1/5(x-1)
==> rearrange to solve for x
4x-4 = 1/5
x - 1 = 1/20
x = 21/20
We also know the y coordinate is 7, which should be equal to 2y+2
7 = 2y + 2
==> rearrange to solve for y
2y = 5
y = 2.5
Our original graph point is (21/20, 5/2)
3 years ago
Answered By Emily D
From the equation they gave us, we know f(1/5(x-1)) = f(4)
So this means that 4 = 1/5(x-1)
==> rearrange to solve for x
4x-4 = 1/5
x - 1 = 1/20
x = 21/20
We also know the y coordinate is 7, which should be equal to 2y+2
7 = 2y + 2
==> rearrange to solve for y
2y = 5
y = 2.5
Our original graph point is (21/20, 5/2)