This is a trinomial. I first suggest you look for gcf between the three terms if it’s there. (4 is the gcf)
4x2 + 8x + 12 = 4(x2 + 2x + 3)
Next you see you have another trinomial. Here, the quickest way to do this is by inspection.
If I multiply (x+a)(x+b),
we have x2+(ax+bx)+ab
or
x2+(a+b)x +ab.
For our trinomial, x2 + 2x + 3
We try to find two numbers that multiply to +3 and add to +2. The only numbers that multiply to 3 are 1 and 3 (prime number), and so there are no two numbers that both add to 2 and multiply to 3. This is therefore not factorable.
The trinomial is therefore factorable only by 4, the greatest common factor between the three terms.
5 years ago
Answered By Emanouil B
4x2 + 8x + 12 = 4(x2 + 2x + 3)
That's it.
5 years ago
Answered By Mina M
This is a trinomial. I first suggest you look for gcf between the three terms if it’s there. (4 is the gcf)
4x2 + 8x + 12 = 4(x2 + 2x + 3)
Next you see you have another trinomial. Here, the quickest way to do this is by inspection.
If I multiply (x+a)(x+b),
we have x2+(ax+bx)+ab
or
x2+(a+b)x +ab.
For our trinomial, x2 + 2x + 3
We try to find two numbers that multiply to +3 and add to +2. The only numbers that multiply to 3 are 1 and 3 (prime number), and so there are no two numbers that both add to 2 and multiply to 3. This is therefore not factorable.
The trinomial is therefore factorable only by 4, the greatest common factor between the three terms.
5 years ago
Answered By Bahareh M
Yes, it is.
First, we could take 4 as a factor;
4 (x2 + 2x + 3)
Then the bracket can be spread to;
4 (x +1) (x + 2)