I've been trying to figure out why  $f\ left(x\ right)=\ SQRT{x+2}$ƒ (x)=√x+2  IS a shift left 2.  I keep thinking that it IS +2 and that means right 2.

Given  $ Y-k=a\ left(x-h\ right)^2$ Y−k=a(x−h)² , a=1, h<0, k>0, which quadrant  is the vertex in?  

if Y=f(x) is reflected in the x-axis, stretched horizontally by a factor of 1/2 and stretched vertically by a factor of 2, what is the new equation?

  write  $2\log_bx-\frac{\log_bZ}{2}$2 log_bx− log_bZ2   as a single logarithm

A and B are in quadrant 1. Sin A = (4/5) and cos B = (7/9). Give an exact value for Sin (A+B).

What is the vertical translation is applied to y=x squared if the transformation graph passes through point (4,19)?

 $\frac{\frac{y=\frac{f\left(x\right)}{ }}{ }}{y=\frac{g\left(x\right)}{ }}$y=ƒ (x)  y=g(x)   

consider the function

(2x^2+x-1)/(x^2-2x-3)

Find

Asymptotes

Point of Discontinuity

Domain 

Range

How does the remainder of P(x)/x-a=Q(x)+R/x-a compare to R/x-a

What does the remainder of this division represent?

If the function of f(x) has a domain of [4,6] and a range of [2,3], what will the domain and range of g(x) be? $\frac{1}{2}g\left(x\right)+2=2f\left(x-3\right)$12 g(x)+2=2ƒ (x−3)