I assume you meant m1*m2 (multiplication)? If that's the case:
Note that here G represents the gravitational constant where it is the same for everthing in the universe. And the equation itself is Newton's law of universal gravitation.
To solve for G we must first multiply both sides by R^2: R^2*F = [(Gm1m2)/R^2]*R^2 thus we can see it gets cancelled out on the right side of the equation so we're left with R^2*F= G(m1m2) now to solve for G simply divide both sides by m1m2. Thus our final result will be:
5 years ago
Answered By Adam S
G=[F*(R^2)]/(m1-m2)
5 years ago
Answered By Arjun S
I assume you meant m1*m2 (multiplication)? If that's the case:
Note that here G represents the gravitational constant where it is the same for everthing in the universe. And the equation itself is Newton's law of universal gravitation.
To solve for G we must first multiply both sides by R^2: R^2*F = [(Gm1m2)/R^2]*R^2 thus we can see it gets cancelled out on the right side of the equation so we're left with R^2*F= G(m1m2) now to solve for G simply divide both sides by m1m2. Thus our final result will be:
G = [(R^2*F)/(m1m2)]