Recombination frequency question. The recombinant frequency of two genes A and B located on the same chromosome is 38%. Parents heterozygous for genes A and B were test crossed, and 250 offspring resulted. How many of the offspring would have the parental genotypes ofr A and B?
I was told that you have to use this formula : recombination frequency= # of recombinant types / total number of offspring x 100%. I did this. I went 0.38= # of recombinant types / 250 offsprings x 100%. i got rid off the 100% to get 0.38 i took 0.38 x 250 i ogt 95. is my answer correct?
6 years ago
Answered By Olena V
Yes, your answer is correct.
The number of offspring that would have the parental genotypes A and B would be 95. The 38% lets you know how often this occurs in a group of offspring. So if you know that your total amount of offspring is 250 you then multiply it by .38 to get your answer of 95 offspring.
Basically this question lets you know that unlike the traditional punett square where if you combine two heterzogous individuals (AB and AB) where the possibility of the offspring to be AB as well is 50%, the chance of that is actually lower (38%).