Regarding last question.
i never learnt that formula we have been using and for all other questions used 1 of two formulas sn=t1(r^n-1) / r-1 or sn=rtn-t1 / r-1
prev question
# 14 in the pre calculus textbook in Alberta
suppose a set of 10 beads were laid in a line where each successive bead had a diameter that was 3/4 of the diameter of the previous bead. If the first bead had a diameter of 24mm, determine the total length of the line of the beads. Express your answer to the nearest millimetre.
7 years ago
if you have not learned this formula, do like below:
S=24+24*(3/4)+24*(3/4)2+...+24*(3/4)9 ?1?
from 1, you can get:
s10 *(3/4)=24*(3/4)+24*(3/4)2 +...+24*(3/4)9+24*(3/4)10 (2)
Then (1)-(2), you get:
s10*(1-3/4)=24-24*(3/4)10
So, S10=24*(1-(3/4)9)/(1-3/4)
the answer is the same.
12 minutes ago
If I'm understanding this correctly you need to set up a sum series function:
$\sum_{x=0}^9=24mm\left(\frac{3}{4}\right)^x$∑x=09=24mm(34 )x
Note that the end of the series is 9, because for many series calculations the end of the series is (x-1).
Plug this formula into your calculator, or an excel sheet if you can, and you should get an answer of 90.59mm which makes the answer: Distance = 91mm.