The safe stopping distance, d, in metres is given by the function d(s) = 0.02(3s*2+20s), where s is the speed of the motorcycle in metres per second. Find the speed at which the safe stopping distance is 50 metres.
4 years ago
d(s)=50 (m)
d(s)=0.02(3s2+20s)
50=0.02(3s2+20s)
2500=3s2+20s
3s2+20s-2500=0
s= $\frac{-20\pm\sqrt{30400}}{6}$−20±√304006
4 years ago
Answered By Mahboubeh D
d(s)=50 (m)
d(s)=0.02(3s2+20s)
50=0.02(3s2+20s)
2500=3s2+20s
3s2+20s-2500=0
s= $\frac{-20\pm\sqrt{30400}}{6}$−20±√304006