two ropes are attached to a heavy box to pull it along the floor. One rope applies a force of 475 N due west, the other applies a force of 315 N due south. What is the net force exerted on the box
2 years ago
Fx = 475 N [W] = -475 N
Fy = 315 N [S] = -315 N
Fnet = sqrt (Fx2 + Fy2) = sqrt ((-475 N)2 + (-315 N)2) = 570 N
Theta = tan-1 (|Fy/Fx|) = tan-1 (315/475) = 33.6 °
Fnet = 570 N [33.6 ° S of W]
2 years ago
Answered By Majid B
Fx = 475 N [W] = -475 N
Fy = 315 N [S] = -315 N
Fnet = sqrt (Fx2 + Fy2) = sqrt ((-475 N)2 + (-315 N)2) = 570 N
Theta = tan-1 (|Fy/Fx|) = tan-1 (315/475) = 33.6 °
Fnet = 570 N [33.6 ° S of W]