If q(x)=x+4, determine q(q(q(q(q(q(q(q(q(q(x^3)))))))))). [Hint: look for a pattern]
8 years ago
Answered By Tomokazu S
q(x)=x+4
q(x3)=x3+4x1
q(q(x3))=q(x3+4)=x3+8=x3+4x2
q(q(q(x3)))=q(x3+8)=x3+12=x3+4x3
Now you can see ten of q in the question.
Therefore the final answer is x3+4x10=x3+40.
8 years ago
Answered By Julius d
Given: q(x) = x + 4
Solve: q(q(q(q(q(q(q(q(q(q(x3))))))))))
Solution: start from the innermost parenthesis.
q(x3) = (x3) + 4
q(q(x3)) = q(x3 + 4) = x3 + 4 + 4
Notice that the answer is an x3 and a bunch of +4's. The number of +4's is actually the same as the number of q's. Therefore for 10 q's (problem), the answer must be x3 + 4(10) which is equal to
x3 + 40
8 years ago
Answered By Jaehoon N
If q(x) = x+4,
q(x3) = x3+4 because the x3 replaces the x from x+4.
So using that concept,
for q(x3+4)
The x3+4 inside the bracket would replace the x from x+4 which would give you: q(x3+4) = (x3+4) +4
So you are now at q(q(q(q(q(q(q(q(x3+8)))))))). The same thing applies for the rest of the equation, which you could simply recognize the arithmetic sequence of x3+4(10) = x3+40.
*10 is the number that is multiplied to the 4 because that is how many q(x)'s or functions are given in the question.*
8 years ago
Answered By Changliang Z
q(X)=X+4
q(x^3)=x^3+4
q(q(x^3))=(x^3+4)^3+4
.......
The final pattern is (((((((((x^3+4)^3+4)^3+4)^3+4)^3+4)^3+4)^3+4)^3+4)^3+4)^3+4
8 years ago
Answered By Changliang Z
My roommate said the answer should be x3+40. I think so.
He said here X=x^3, so I did not answer this question by X but x. Sorry
8 years ago
Answered By Victor Luis F
(g(x3)n=(10)n(x3+4)
appliying log in both sides of the equation and afterwards returning with the power of 10 in both
sides of the equation
8 years ago
Answered By Victor Luis F
Sorry I will like to make a correction to my answer, the answer is the following:
8 years ago
Answered By Tomokazu S
q(x)=x+4
q(x3)=x3+4x1
q(q(x3))=q(x3+4)=x3+8=x3+4x2
q(q(q(x3)))=q(x3+8)=x3+12=x3+4x3
Now you can see ten of q in the question.
Therefore the final answer is x3+4x10=x3+40.
8 years ago
Answered By Julius d
Given: q(x) = x + 4
Solve: q(q(q(q(q(q(q(q(q(q(x3))))))))))
Solution: start from the innermost parenthesis.
q(x3) = (x3) + 4
q(q(x3)) = q(x3 + 4) = x3 + 4 + 4
Notice that the answer is an x3 and a bunch of +4's. The number of +4's is actually the same as the number of q's. Therefore for 10 q's (problem), the answer must be x3 + 4(10) which is equal to
x3 + 40
8 years ago
Answered By Jaehoon N
If q(x) = x+4,
q(x3) = x3+4 because the x3 replaces the x from x+4.
So using that concept,
for q(x3+4)
The x3+4 inside the bracket would replace the x from x+4 which would give you: q(x3+4) = (x3+4) +4
So you are now at q(q(q(q(q(q(q(q(x3+8)))))))). The same thing applies for the rest of the equation, which you could simply recognize the arithmetic sequence of x3+4(10) = x3+40.
*10 is the number that is multiplied to the 4 because that is how many q(x)'s or functions are given in the question.*
8 years ago
Answered By Changliang Z
q(X)=X+4
q(x^3)=x^3+4
q(q(x^3))=(x^3+4)^3+4
.......
The final pattern is (((((((((x^3+4)^3+4)^3+4)^3+4)^3+4)^3+4)^3+4)^3+4)^3+4)^3+4
8 years ago
Answered By Changliang Z
My roommate said the answer should be x3+40. I think so.
He said here X=x^3, so I did not answer this question by X but x. Sorry
8 years ago
Answered By Victor Luis F
(g(x3)n=(10)n(x3+4)
appliying log in both sides of the equation and afterwards returning with the power of 10 in both
sides of the equation
8 years ago
Answered By Victor Luis F
Sorry I will like to make a correction to my answer, the answer is the following:
g(x3)=(x3+4)n